WebQuestion: (3 points) Find the equation in \( x \) and \( y \) for the line tangent to the curve given parametrically by \[ x=3 t+4, \quad y=t^{2}-1 \] at the point on the curve associated with \( t=-2 \). \[ y= \] Problem 2. (3 points) Consider the curve given parametrically by \[ x(t)=6 t^{3}-5, \quad y(t)=t^{2}-t+7 \] For what value of \( t ... WebQuestion: Consider the curve given by the equation 2(x - y) = 3 + cos y. For all points on the curve CI (a) Show that - sin y (b) For y t here is a point P on the curve through …
calculus - Find equations of the tangents to a parametric curve …
WebConsider the parametric equations below. x = t2 − 2, y = t + 4, −3 ≤ t ≤ 3. (a) Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as t increases. (b) Eliminate the parameter to find a Cartesian equation of the curve. for. 1 ≤ y ≤ 7. WebConsider the curve given by the equation : 2y^3 + y^2 - y^5 = x^4 -2x^3 +x^2 Find all points at which the tangent line to the curve is horizontal or vertical. Thanks! This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer bayaran peguam
Answered: 2. For this problem, consider the… bartleby
WebJun 4, 2024 · $\begingroup$ Right, through (4,3) there is tangent at that point but slope form of line $(y-3)=-2(x-4)$ equation crosses curve not touching it. Also there is difference between secant ,tangent line and normal line definition. $(y-3)=-2(x-4)$ This line doesn't fit the definition of tangent line as you can see in graph. WebConsider the parametric equations below. x = 1 + 3 t, y = 2 − t 2 (a) Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as t increases. (i (b) Eliminate the varameter to find a Cartesian equation of the curve. WebConsider the curve with parametric equation The equation of the: a(t)= [t+ 3,3t2 +t +1],t ∈ R - tangent to the curve at the point a(1) is y = - normal to the curve at the point a(1) is y = By eliminating the parameter t, we find that the Cartesian equation of the curve is: y = Previous question Next question This problem has been solved! davi 7 anos