In an ap the sum of first n terms is 5n 2/2

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WebAug 28, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term. Advertisement Expert-Verified Answer 1282 people found it helpful Brainly User Let the … WebThe sum of the first n term sofa an AP is ( 3 n 2 2 + 5 n 2). Find its nth term and the 25th term Advertisement Remove all ads Solution Let S denotes the sum of first n terms of the AP. ∴ s n = ( 3 n 2 2 + 5 n 2) ⇒ s n - 1 = 3 ( n - 1) 2 2 + 5 ( n - 1) 2 = 3 ( n 2 - 2 n + 1) 2 + 5 ( n - 1) 2 = 3 n 2 - n - 2 2 ∴ n th term pf the AP , a n

The Sum of the First N Term Sofa an Ap is ` ( (3n^2) /2 + (5n) /2 ...

WebAnswer (1 of 3): If a is initial term & d is the common difference, then Sn = { 2a + ( n - 1 ) *d } * n/2 So S2n = { 2a + ( 2n - 1) *d } * n = 2an + 2n^2d - nd = (2a -d)n + 2n^2d = 3n + 14 n^2 Comparing coefficients with terms of n & n^2 we observe 2a - … WebNov 11, 2011 · Find the sum of first n terms if an AP whose nth term is 5n-1. Hence find the sum of first 20 terms Asked by 11 Nov, 2011, 04:16: PM Expert Answer n th term = 5n - 1 Put n=1, we get 1 st term = 5-1 = 4 Hence sum of n terms = n (First term + nth term)/2 = n (4+5n - 1)/2 = n (5n +3)/2 Sum of 20 terms becomes, put n = 20 S 20 = 20 (5×20 +3)/2 northeast region of the united states

Akrthmetic Progressions 115 EXERCISE 5.4 (Optional)* 1. Which term …

WebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... WebThe sum of first n terms of an A.P is given by S n=2n 2+3n. Find the sixteenth term of the A.P Easy Solution Verified by Toppr Sn= 2n(2a+(n−1)d) = 2n(2a−d)+n 22d=2n 2+3n ∴2= 2d⇒=4 and 22a−d=3 ∴2a=6+d=10 or, a=5. ∴a 16=a+(1+−1)d =5+15×4=65. Was this answer helpful? 0 0 Similar questions WebJun 22, 2024 · According to the given problem The ratio of the sums of first n terms of two A.P.s = (5n+13) : (7n +27 ) = (5n+13) / (7n +27 ) --------------- (4) (3) and (4) are equal. => [2a+ (n-1)d]/ [2b+ (n-1)c] = (5n+13)/ (7n+27) To find ratio of 4 terms , write n = 7 since (2×4-1)=7 => [2a+ (7-1)d]/ [2b+ (7-1)c]= (5 (7)+13))/ (7 (7)+27)) northeast rehab at cedardale

In an AP, if Sₙ = 3n² + 5n and ak = 164, find the value of k - Cuemath

Ex 9.2, 7 - Find sum n terms of AP, whose kth term is 5k + 1

WebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebIn an A.P the sum of first n terms is 3n2/2 + 13n/2. Find the 25th term arithmetic progression cbse class-10 1 Answer +1 vote answered Sep 30, 2024 by KajalAgarwal (45.2k points) selected Oct 1, 2024 by Vikash Kumar Best answer Given, Sn = 3n2/2 + 13n/2 ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test … how to reverse a string in java arrayWebApr 10, 2024 · Sum of first n terms of an AP S n = n 2 [ 2 a + ( n − 1) d] Where a =1st term & d =common difference Or, S n = n 2 [ a + a n] If there are only n terms in an AP, then a n =l, l=last term We will put n=1, 2 in the sum formula and evaluate the first and second term of the A.P. Then we can easily derive the common difference. By putting all these in how to reverse a string in c using pointers

"WebGiven, the expression for the sum of the series is Sₙ = 3n² + 5n. Last term, l is a k = 164. We have to find the value of k. Put n = 1, S₁ = 3(1)² + 5(1) = 3 + 5 = 8. ... If the sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, find the sum of th . . . . " - In an ap the sum of first n terms is 5n 2/2

In an ap the sum of first n terms is 5n 2/2

In an arithmetic progression the sum of the first n term,denoted by S_n …

WebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term is NOT known is S n = (n/2) [2a + (n - 1) d]; The sum of first n terms of an arithmetic progression when the n th term(a n) is known is S n = n/2[a 1 + a n]; Example: Mr. Kevin …

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WebMar 30, 2024 · Given Sn = 2n2 + 3n Taking n = 1 S1 = 2 12 + 3 1 = 2 + 3 = 5 So, Sum of first term of AP is 5 But sum of first term will be the first term So, First term = a = 5 Taking n = 2 in Sn S1 = 2 22 + 3 2 S2 = 2 4 + 6 S2 = 8 + 6 S2 = 14 Sum of first 2 terms is 14 Finding 2nd term Sum of first 2 terms is 14 First term + Second term = 14 5 + a2 = 14 a2 = … WebLet S denotes the sum of first n terms of the AP. `∴ s_n = ( (3n^2) /2 +(5n) /2)` `⇒ s_(n-1) = (3(n-1)^2)/2 + (5 (n-1))/2` `= (3(n^2 - 2 n + 1 ))/2 + (5 (n-1))/2` `=(3n^2 - n-2)/2` ∴ n th term …

WebGeneral term of an AP is given by: a n = S n - S (n - 1) Calculation: Given: S n = 5n 2 + 6n and m th tem is 301. a n = S n - S (n - 1) After solving above equation we get . a n = 5(n) 2 + 6(n) - [5(n - 1) 2 + 6(n - 1)] a n = 5n 2 + 6n - 5n 2 - 5 + 10n - 6n + 6. a n = 10n + 1 . For 1st term, put n = 1. So, a 1 = 10 × 1 + 1 = 11. For 2nd term ... WebSolution Given that sum of the first n terms of an AP is 5n - n 2 Sn = 5n − n 2 First term, a 1 = S 1 = 5 (1) − (1) 2 = 5 − 1 = 4 Sum of first two terms = S 2 = 5 (2) − (2) 2 = 10 − 4 = 6. …

WebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... WebIf the nth term of an A.P. is 4n^2 - 5n, what is the sum of the first n term? Given that nth term of an A.P = Note that in any AP, nth term is always linear equation in and cannot be in second degree. However, the sum of first terms of an AP is a second degree equation in .

WebApr 16, 2024 · If the sum of first n terms is (3n2 + 5n), find its common difference. LIVE Course for free. ... If the sum of n terms of an A.P. is 3n^2 + 5n and its mth term is 164, find the value of m. ... In an AP, if Sn = 3n^2 + 5n and ak = 164, then find the value of k.

WebApr 20, 2024 · Apr 20, 2024 The sum of the first n term of an AP,denoted by Sn is given by Sn = n2 +8n So n th term of the series will be tn = Sn −Sn−1 = n2 + 8n − ((n −1)2 +8(n − 1)) ⇒ tn = 2n − 1 + 8 = 2n +7 Inserting n = 1,2,3.... we get For n = 1 → t1 = 2 ⋅ 1 +7 = 9 For n = 2 → t2 = 2 ⋅ 2 +7 = 11 For n = 3 → t3 = 2 ⋅ 3 +7 = 13 Hence first term t1 = 9 northeast rehab at elliot hospitalWebSo, the sum of the first n terms of an AP is given by S = n/2 [2a + (n 1) d] We can also write as S = n/2 [a + a + (n 1) d] S = n/2 [a + an] (iii) If there are only n terms in an AP, then a n = l, the last term. From (iii), S = n/2 [a + l] (iv) northeast rehab beverly maWebJul 12, 2024 · Best answer Let Sn denotes the sum of first n terms of the AP. ∴ Sn = 5n - n2 ⇒ ⇒ Sn-1 = 5 (n - 1) - (n - 1)2 = 5n - 5 - n2 + 2n - 1 = 7n - n2 - 6 ∴ nth term of the AP, an = Sn … northeast rehab at elliotWebThe sum of the first n terms of an AP in ( 5 n 2 2 + 3 n 2) .Find its nth term and the 20th term of this AP. Advertisement Remove all ads Solution s n = ( 5 n 2 2 + 3 n 2) = 1 2 ( 5 n 2 + 3 n) ..... (1) Replacing n by (n-1) in (i), we get: s n - 1 = 1 2 × [ 5 ( n - 1) 2 + 3 ( n - 1)] = 1 2 × [ 5 n 2 - 10 n + 5 + 3 n - 3] = 1 2 × [ 5 n 2 - 7 n + 2] northeast rehab chelmsford maWebSum of ‘n’ terms of an A.P. 6 mins. Symmetric Representation of Three or More Terms in an A.P. 6 mins. Find a Value of Expression in AP using a Short Approach I. 4 mins. Find a … how to reverse a track in soundtrapWebThe sum of the first n terms of an AP in ( 5 n 2 2 + 3 n 2) .Find its nth term and the 20th term of this AP. Advertisement Remove all ads Solution s n = ( 5 n 2 2 + 3 n 2) = 1 2 ( 5 n 2 + 3 … how to reverse a string in java using stackWebAug 29, 2024 · If sum to n terms of an A.P. is 5n2 +6n and rth term is 401, then the value of r is Advertisement Expert-Verified Answer 19 people found it helpful Cosmique Answer: Value of r is 40 Explanation: Given, Sum of n terms of an AP is 5 n² + 6 n rth term of AP = aᵣ = 401 To find, Value of r So, Finding the AP how to reverse a string in java word by word